RandomVector(Count: Integer): Array;
Count. Vector length.
The RandomVector method returns the vector of random numbers corresponding to the distribution.
To execute the example, the form must have the ChartBox component and the UiChart component which serves as the source for ChartBox.
Class MyForm: Form
ChartBox1: ChartBox;
UiChart1: UiChart;
Uniform: SmUniformDistribution;
Values: Array Of Double;
Const Cnt = 10;
Sub MyFormOnCreate(Sender: Object; Args: IEventArgs);
Begin
Uniform := New SmUniformDistribution.Create;
Text := Uniform.DisplayName;
Uniform.A := 0.1;
Uniform.B := 0.8;
Values := Uniform.RandomVector(Cnt);
UiChart1.PointCount := cnt;
End Sub MyFormOnCreate;
Sub UiChart1OnGetDataValue(Sender: Object; Args: IUiChartGetDataValueEventArgs);
Begin
If Args.PointIndex < Cnt Then
Args.Value := Values[Args.PointIndex];
Args.Result := True;
End If;
End Sub UiChart1OnGetDataValue;
End Class MyForm;
After executing the example a uniform distribution graph is created for the value:
See also: